Unit 1 — Dynamic Electricity and Electromagnetism · Physics. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 80 questions on this lesson, each with an explanation.
The iron core of a transformer is built from thin laminated sheets insulated from one another mainly to…
Araise the frequency of the alternating current
Bincrease the eddy currents in the core
Creduce the energy lost as heat by eddy currents
Dincrease the ohmic resistance of the primary coil
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Correct answer: (C) reduce the energy lost as heat by eddy currents
Explanation: Lamination raises the resistance of the eddy-current paths, reducing the heat energy dissipated by eddy currents in the core.
Question 2Easy
A straight conducting rod of length L moves with velocity v perpendicular to a uniform magnetic field of flux density B. The motional electromotive force induced across the rod is given by…
AL v / B
BB L v
CB v / L
DB L / v
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Correct answer: (B) B L v
Explanation: The motional emf of a straight wire moving perpendicular to B is VB = B L v.
Question 3Easy
In an AC generator, the instantaneous induced emf reaches its maximum value at the instant when the plane of the coil is…
Aparallel to the magnetic field lines
Bat an angle of 45° to the field lines
Cperpendicular to the magnetic field lines
Dcompletely outside the magnetic field
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Correct answer: (A) parallel to the magnetic field lines
Explanation: The emf is maximum when the coil plane is parallel to the field lines, where the flux is zero and its rate of change is greatest.
Question 4Medium
Eddy currents are usefully employed in…
Athe electromagnetic braking system of trains
Bincreasing the resistance of transmission cables
Cinsulating the windings of a coil
Dstoring electric charge in a capacitor
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Correct answer: (A) the electromagnetic braking system of trains
Explanation: Electromagnetic (eddy-current) brakes rely on eddy currents induced in a moving metal disc to oppose its motion.
Question 5Medium
A conducting rod of length 0.5 metre slides at 4 m/s along parallel rails placed in a magnetic field of flux density 0.2 T. If the circuit has a total resistance of 2 Ω, the induced current in the rod equals…
A0.4 A
B0.1 A
C0.8 A
D0.2 A
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Correct answer: (D) 0.2 A
Explanation: VB = BLv = 0.2 × 0.5 × 4 = 0.4 V, so I = VB/R = 0.4/2 = 0.2 A.
Question 6Medium
A coil of area 0.02 m² is placed in a uniform magnetic field of flux density 0.4 T so that the normal to its plane makes an angle of 60° with the field. The magnetic flux Φₘ through the coil equals…
A coil of self-inductance 2 H carries a current that increases uniformly from 3 A to 7 A in 0.5 s. The magnitude of the self-induced emf is…
A8 V
B16 V
C32 V
D12 V
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Correct answer: (B) 16 V
Explanation: VB = L (ΔI/Δt) = 2 × (7 − 3) / 0.5 = 16 V.
Question 8Hard
A solenoid of 200 turns carries a current of 4 A, producing a magnetic flux Φₘ of 0.02 Wb through each turn. The self-inductance coefficient L of the solenoid equals…
A1 H
B0.5 H
C10 H
D2 H
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Correct answer: (A) 1 H
Explanation: L = N·Φₘ/I = 200 × 0.02 / 4 = 1 H.
Question 9Hard
A square coil of side 0.1 metre and 80 turns lies perpendicular to a magnetic field. The flux density increases uniformly from 0.2 T to 0.7 T in 0.05 s. The magnitude of the induced electromotive force equals…
Two coils are wound on the same core. When the current in the primary changes from 2 A to 6 A in 0.1 s, the flux linking each of the 300 turns of the secondary changes by 8 × 10⁻⁴ weber. The mutual inductance and the induced secondary emf are respectively…
AM = 0.06 H, emf = 24 V
BM = 0.6 H, emf = 24 V
CM = 0.6 H, emf = 2.4 V
DM = 0.06 H, emf = 2.4 V
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Correct answer: (D) M = 0.06 H, emf = 2.4 V
Explanation: emf₂ = N₂ ΔΦ/Δt = 300 × 8 × 10⁻⁴ / 0.1 = 2.4 V, and M = emf₂ ÷ (ΔI₁/Δt) = 2.4 / 40 = 0.06 H.