Chapter Two · Firstly: Qualitative chemical analysis: practice questions
Chapter Two · Chemical analysis · Chemistry. These are 10 questions from the Magmo3 bank on this lesson, from easy to hard. Solve each one, then open "Show answer and explanation". Magmo3 has 116 questions on this lesson, each with an explanation.
In the detection of the sulphite anion, what is the observation when a paper wet with potassium dichromate acidified by sulphuric acid is exposed to the evolved gas?
AThe paper turns black
BThe paper turns blue
CThe paper turns green
DThe paper turns yellow
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Correct answer: (C) The paper turns green
Explanation: Sulphur dioxide gas evolved turns a paper wet with potassium dichromate acidified by sulphuric acid to green.
Question 2Easy
In the classical scheme of cation analysis, which reagent is used as the group reagent to precipitate the cations of the first analytical group (such as Ag⁺ and Pb²⁺) as insoluble chlorides?
Explanation: The first analytical group is precipitated as insoluble chlorides by dilute hydrochloric acid.
Question 3Easy
Which reagent is used to confirm the presence of sulphide (S²⁻) ions in a solution?
APotassium dichromate acidified by sulphuric acid.
BPotassium permanganate.
CSilver nitrate solution.
DStarch paper.
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Correct answer: (C) Silver nitrate solution.
Explanation: 'Salt solution + silver nitrate solution black ppt. is formed' as the confirmatory test for sulphide.
Question 4Medium
In the brown ring test for the nitrate ion, concentrated sulphuric acid is carefully poured down the side of the tube. The brown ring formed at the junction of the two liquids is due to the formation of:
Asilver chloride (AgCl)
Blead(II) sulphide (PbS)
Cthe brown-ring compound FeSO₄.NO
Dbarium sulphate (BaSO₄)
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Correct answer: (C) the brown-ring compound FeSO₄.NO
Explanation: Part of the nitrate is reduced by iron(II) sulphate in the presence of conc. H₂SO₄, giving nitric oxide (NO). NO combines with FeSO₄ to form the brown-ring compound FeSO₄.NO at the junction of the two liquids.
Question 5Medium
Why is the qualitative analysis of a mixture more complex than that of a pure substance?
ABecause mixtures always require gravimetric analysis before qualitative analysis.
BBecause mixtures must first be separated into their components before identifying them using suitable indicators.
CBecause pure substances cannot be identified by physical constants like boiling point.
DBecause qualitative analysis is not applicable to mixtures containing more than two components.
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Correct answer: (B) Because mixtures must first be separated into their components before identifying them using suitable indicators.
Explanation: If it is a mixture, firstly we must separate their component then identify them by the chemical method using suitable indicator.
Question 6Medium
A solution contains a single anion. It gives no precipitate with barium chloride, a white precipitate with silver nitrate that dissolves in concentrated ammonia, and no gas with dilute acid. The anion is the:
Asulphide ion
Bchloride ion
Csulphate ion
Dcarbonate ion
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Correct answer: (B) chloride ion
Explanation: No precipitate with BaCl₂ rules out sulphate; no gas with dilute acid rules out carbonate and sulphide; a white AgCl precipitate soluble in concentrated ammonia confirms the chloride ion.
Question 7Medium
Which of the following observations distinguishes a nitrite (NO₂⁻) from a nitrate (NO₃⁻)?
AOnly the nitrate gives a white precipitate with barium chloride.
BOn adding dilute hydrochloric acid, only the nitrite evolves a colourless gas that turns reddish-brown at the mouth of the tube.
COnly the nitrate turns lead(II) acetate paper black.
DOnly the nitrate decolourises potassium permanganate acidified with conc. sulphuric acid.
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Correct answer: (B) On adding dilute hydrochloric acid, only the nitrite evolves a colourless gas that turns reddish-brown at the mouth of the tube.
Explanation: The nitrite reacts with dilute HCl, giving colourless NO that turns reddish-brown at the mouth of the tube. The nitrate belongs to the conc. sulphuric acid group, and it is the nitrite (not the nitrate) that decolourises acidified permanganate.
Question 8Hard
Consider the following two reactions involving sodium thiosulphate: (1) reaction with dilute HCl yielding a yellow precipitate, and (2) reaction with iodine solution where the brown colour is removed producing sodium tetrathionate. Which species is specifically responsible for the yellow precipitate in the first reaction?
ASilver sulphide (Ag₂S)
BSilver sulphite (Ag₂SO₃)
CSuspended sulphur (S)
DNitrogen dioxide (NO₂)
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Correct answer: (C) Suspended sulphur (S)
Explanation: For thiosulphate with HCl: 'Sulphur dioxide gas evolved and yellow ppt. as a result of suspend sulphur in solution'.
Question 9Hard
A solution contains a mixture of Fe³⁺ and Al³⁺ ions. Sodium hydroxide solution is added slowly until it is in large excess. Which of the following correctly describes the sequence of observations?
ANeither hydroxide precipitates because both are amphoteric
BBoth hydroxides precipitate; the reddish-brown Fe(OH)₃ dissolves in excess, leaving white Al(OH)₃
CBoth hydroxides precipitate; the white Al(OH)₃ dissolves in excess, leaving a reddish-brown Fe(OH)₃ precipitate
DOnly Fe(OH)₃ precipitates; the Al³⁺ stays in solution throughout
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Correct answer: (C) Both hydroxides precipitate; the white Al(OH)₃ dissolves in excess, leaving a reddish-brown Fe(OH)₃ precipitate
Explanation: Al(OH)₃ is amphoteric and dissolves in excess sodium hydroxide, while basic Fe(OH)₃ remains as a reddish-brown precipitate, allowing separation.
Question 10Hard
If you have an unknown solid inorganic salt and you add dilute hydrochloric acid, no gas evolves. Then you test a solution of the salt with silver nitrate solution, and it forms a yellow precipitate that is insoluble in ammonia solution. Which anion is most likely present?
AIodide (I¯)
BChloride (Cl¯)
CBromide (Br¯)
DSulphite (SO3)2-
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Correct answer: (A) Iodide (I¯)
Explanation: Under Iodide (I⁻) confirmatory test: Salt solution + silver nitrate solution yellow ppt. is formed from silver iodide insoluble in ammonia solution.